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b- c + a > b + c + a and c b a < c + b a
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07 Jan 2023, 01:39
07 Jan 2023, 01:39
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Question Stats:
56% (01:38) correct
43% (01:34) wrong based on 53 sessions
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\(b − c + a > b + c + a\) and \(c − b − a < c + b − a\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
b |
c |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: b- c + a > b + c + a and c b a < c + b a
[#permalink]
31 Jan 2023, 10:49
31 Jan 2023, 10:49
Expert Reply
OE
The first inequality simplifies to:
b − c + a > b + c + a
− c + a > c + a
− c > c
0 > 2c
c < 0
The second inequality simplifies to:
c − b − a < c + b − a
−b − a < b − a
−b < b
0 < 2b
b > 0
Because b is positive and c is negative, b must be larger. Therefore, Quantity A is greater.
The first inequality simplifies to:
b − c + a > b + c + a
− c + a > c + a
− c > c
0 > 2c
c < 0
The second inequality simplifies to:
c − b − a < c + b − a
−b − a < b − a
−b < b
0 < 2b
b > 0
Because b is positive and c is negative, b must be larger. Therefore, Quantity A is greater.
Re: b- c + a > b + c + a and c b a < c + b a
[#permalink]
12 May 2025, 21:01
12 May 2025, 21:01
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