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Box A has 10 green balls and 8 black balls.
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31 Aug 2022, 04:50
31 Aug 2022, 04:50
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Box A has 10 green balls and 8 black balls.
Box B has 9 green balls and 5 black balls.
What is the probability if one ball is drawn from each box that both balls are green?
(A) 5/9
(B) 19/252
(C) 10/49
(D) 5/14
(E) 9/14
Box B has 9 green balls and 5 black balls.
What is the probability if one ball is drawn from each box that both balls are green?
(A) 5/9
(B) 19/252
(C) 10/49
(D) 5/14
(E) 9/14
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Re: Box A has 10 green balls and 8 black balls.
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06 Sep 2022, 11:54
06 Sep 2022, 11:54
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SeaOyster1 wrote:
Box A has 10 green balls and 8 black balls.
Box B has 9 green balls and 5 black balls.
What is the probability if one ball is drawn from each box that both balls are green?
(A) 5/9
(B) 19/252
(C) 10/49
(D) 5/14
(E) 9/14
Box B has 9 green balls and 5 black balls.
What is the probability if one ball is drawn from each box that both balls are green?
(A) 5/9
(B) 19/252
(C) 10/49
(D) 5/14
(E) 9/14
Total balls in box A - 18
Total balls in box B - 14
Prob. of picking a green ball from box A = \(\frac{10}{18} = \frac{5}{9}\)
Prob. of picking a green ball from box B = \(\frac{9}{14}\)
Prob. of picking both the balls together = \((\frac{5}{9})(\frac{9}{14}) = \frac{5}{14}\)
Hence, option D
gmatclubot
Re: Box A has 10 green balls and 8 black balls. [#permalink]
06 Sep 2022, 11:54
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