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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Box W and Box V each contain several blue sticks and red sticks, and a
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26 Jun 2022, 22:55
26 Jun 2022, 22:55
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Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length. The length of each red stick is 18 inches less that the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average (arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?
(A) 3
(B) 6
(C) 12
(D) 18
(E) 24
(A) 3
(B) 6
(C) 12
(D) 18
(E) 24
Re: Box W and Box V each contain several blue sticks and red sticks, and a
[#permalink]
30 Jun 2022, 07:44
30 Jun 2022, 07:44
Expert Reply
For the question with 19 and 6 inches correct answer is 25:
{Average lengths of sticks in W} - 19 = Length of red;
{Average lengths of sticks in V} + 6 = Length of red;
{Average W}-19={Average V}+6 --> {Average W}-{Average V}=25.
For the question with 18 and 6 inches correct answer is 24:
{Average lengths of sticks in W} - 1 = Length of red;
{Average lengths of sticks in V} + 6 = Length of red;
{Average W}-18={Average V}+6 --> {Average W}-{Average V}=24.
{Average lengths of sticks in W} - 19 = Length of red;
{Average lengths of sticks in V} + 6 = Length of red;
{Average W}-19={Average V}+6 --> {Average W}-{Average V}=25.
For the question with 18 and 6 inches correct answer is 24:
{Average lengths of sticks in W} - 1 = Length of red;
{Average lengths of sticks in V} + 6 = Length of red;
{Average W}-18={Average V}+6 --> {Average W}-{Average V}=24.
gmatclubot
Re: Box W and Box V each contain several blue sticks and red sticks, and a [#permalink]
30 Jun 2022, 07:44
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