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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
By how much does the larger root of the equation 2x^2+5x = 12 exceed t
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28 Dec 2022, 09:54
28 Dec 2022, 09:54
Expert Reply
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Question Stats:
100% (01:25) correct
0% (00:00) wrong based on 3 sessions
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By how much does the larger root of the equation 2x^2+5x = 12 exceed the smaller root?
(A) 5/2
(B) 10/3
(C) 7/2
(D) 14/3
(E) 11/2
(A) 5/2
(B) 10/3
(C) 7/2
(D) 14/3
(E) 11/2
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: By how much does the larger root of the equation 2x^2+5x = 12 exceed t
[#permalink]
30 Dec 2022, 23:18
30 Dec 2022, 23:18
Expert Reply
Re-writing the equation as follows:
\(2x^2 + 5x - 12 =0\)
The two factors of -24 (-12 x 2) are 8 & -3
So,\(2x^2 + 8x - 3x - 12 = 0\)
2x (x +4) -3 (x+4) = 0
(2x -3) (x+4) = 0
So \(x = \frac{3}{2}\) or x = -4
Distance between 3/2 & -4 =
\(\frac{3}{2} - (-4) = \frac{11}{2}\)
Answer: E
\(2x^2 + 5x - 12 =0\)
The two factors of -24 (-12 x 2) are 8 & -3
So,\(2x^2 + 8x - 3x - 12 = 0\)
2x (x +4) -3 (x+4) = 0
(2x -3) (x+4) = 0
So \(x = \frac{3}{2}\) or x = -4
Distance between 3/2 & -4 =
\(\frac{3}{2} - (-4) = \frac{11}{2}\)
Answer: E
gmatclubot
Re: By how much does the larger root of the equation 2x^2+5x = 12 exceed t [#permalink]
30 Dec 2022, 23:18
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