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Celia has exactly 3 times as many French as non-French photographs in
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13 Oct 2021, 04:15
13 Oct 2021, 04:15
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Celia has exactly 3 times as many French as non-French photographs in her collection. Which of the following CANNOT be the number of photographs in Celia's collection?
100
84
76
69
32
100
84
76
69
32
Show: :: AFTER
Since we know that 3 out of every 4 of Celia's photographs is a French photograph, and photographs do not come in fractions, we know that the amount of photographs in the collection must be evenly divisible by 4.
A:100/4 = 25 (This would mean 25 non-French photographs and 75 French photographs.)
B: 84/4 = 21
C: 76/4 = 19
D: 69/4 = 17.25 (This is the problematic one - it would mean 17.25 non-French photographs, which is impossible.)
E: 32/4 = 8
Answer D.
A:100/4 = 25 (This would mean 25 non-French photographs and 75 French photographs.)
B: 84/4 = 21
C: 76/4 = 19
D: 69/4 = 17.25 (This is the problematic one - it would mean 17.25 non-French photographs, which is impossible.)
E: 32/4 = 8
Answer D.
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Re: Celia has exactly 3 times as many French as non-French photographs in
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13 Oct 2021, 04:32
13 Oct 2021, 04:32
1
Carcass wrote:
Celia has exactly 3 times as many French as non-French photographs in her collection. Which of the following CANNOT be the number of photographs in Celia's collection?
100
84
76
69
32
100
84
76
69
32
Let x = the number of non-French photographs in the collection
So, 3x = the number of French photographs in the collection
So, the TOTAL number of photographs in the collection = x + 3x = 4x.
This means the TOTAL number of photographs in the collection must be a multiple of 4
100, 84, 76 and 32 are all multiples of 4
69 is NOT a multiple of 4
Answer: D
gmatclubot
Re: Celia has exactly 3 times as many French as non-French photographs in [#permalink]
13 Oct 2021, 04:32
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