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d(d2 – 2d + 1) vs d(d2 – 2d) + 1
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23 Jun 2018, 12:13
23 Jun 2018, 12:13
Expert Reply
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Question Stats:
87% (00:36) correct
12% (00:28) wrong based on 93 sessions
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Quantity A |
Quantity B |
\(d(d^2 - 2d + 1)\) |
\(d(d^2 - 2d) + 1\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: d(d2 – 2d + 1) vs d(d2 – 2d) + 1
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28 Jun 2018, 16:45
28 Jun 2018, 16:45
sandy wrote:
Quantity A |
Quantity B |
\(d(d^2 - 2d + 1)\) |
\(d(d^2 - 2d) + 1\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Here ;
Statement 1: \(d(d^2 - 2d + 1)\) =\(d^3 - 2d^2 + d\)
Statement 2 : \(d(d^2 - 2d) + 1\) = \(d^3 - 2d^2 + 1\)
So\(d^3 - 2d^2\) is common in both the statement and can be neglected.
so we are left with "d" in statement 1 and "1" in statement 2
But we donot have any information about d, so d can be > 1 or d can be < 1
Hence option D.
Re: d(d2 – 2d + 1) vs d(d2 – 2d) + 1
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17 Jul 2018, 12:04
17 Jul 2018, 12:04
Expert Reply
Explanation
In Quantity A, multiply d by every term in the parentheses:
\(d(d^2 - 2d + 1) = (d \times d^2) - (d \times 2d) + (d \times 1) = d^3 - 2d^2 + d\)
In Quantity B, multiply d by the two terms in the parentheses:
\(d(d^2 - 2d) + 1 = (d \times d^2) - (d \times 2d) + 1 = d^3 - 2d^2 + 1\)
Because \(d^3 - 2d^2\) is common to both quantities, it can be ignored. The comparison is really between d and 1. Without more information about d, the relationship cannot be determined from the information given.
In Quantity A, multiply d by every term in the parentheses:
\(d(d^2 - 2d + 1) = (d \times d^2) - (d \times 2d) + (d \times 1) = d^3 - 2d^2 + d\)
In Quantity B, multiply d by the two terms in the parentheses:
\(d(d^2 - 2d) + 1 = (d \times d^2) - (d \times 2d) + 1 = d^3 - 2d^2 + 1\)
Because \(d^3 - 2d^2\) is common to both quantities, it can be ignored. The comparison is really between d and 1. Without more information about d, the relationship cannot be determined from the information given.
