GeminiHeat wrote:
Different breeds of dogs get older at different rates in “dog years.” Livonian wolfhounds age 7 times as fast as humans, whereas Khazarian terriers age 5 times as fast and Akkadian retrievers age 4 times as fast. If Dan bought a newborn Akkadian on January 1, 2010, a newborn Khazarian 1 year later, and a newborn Livonian 1 year after that, in what year will the sum of the dog-year ages of the Akkadian and the Khazarian first be exceeded by twice the age of the Livonian in dog years, rounding all ages down to the nearest integer?
A. 2013
B. 2014
C. 2015
D. 2016
E. 2017
Let,
age of Humans = H
age of Akkadian retrievers = A
age of Khazarian terriers = K
age of Livonian wolfhounds = L
Given;
A = 4H
K = 5H
L = 7H
1 Human year is 4 years for A, 5 years for K, and 7 years for L
To find: In what year will the sum of the dog-year ages of the Akkadian and the Khazarian first be
exceeded by twice the age of the Livonian in dog years
i.e \(A + K < 2L\)
2010: (A) (_) (_)
2011: (4) (K) (_)
2012: (8) (5) (L)
2013: (12) (10) (7) ...... 12 + 10 < 2(7)
2014: (16) (15) (14) ...... 16 + 15 < 2(14)
2015: (20) (20) (21) ...... 20 + 20 < 2(21)2016:
2017:
Hence, option C