ferdousrakib wrote:
Attachment:
#GREpracticequestion In the below addition A, B, C, D, E, F,.png
In the below addition A, B, C, D, E, F, and G represent the digits 0, 1, 2, 3, 4, 5 and 6. If each variable has a different value, and E ≠ 0, then G equals to which of the following
A) 2
B) 3
C) 4
D) 5
E) 6
If we add two 2-digit numbers and the sum is a 3-digit number, then the 3-digit number must start with a 1.
So,
E = 1In order for the sum to be a 3-digit number, A+C must be greater than 9
So, we have two options:
EITHER A and C are 5 and 6, OR A and C are 4 and 6
If A and C are 5 and 6, then F = 1, but we already know that E = 1
So, it MUST be the case that
A and C are 4 and 6, which means
F = 0The three digits unaccounted for are 2, 3 and 5
Since we can see that B + D = G, it must be the case that
G = 5Answer: D
Cheers,
Brent
_________________
Brent Hanneson - founder of Greenlight Test Prep