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Each term of a certain sequence is calculated by adding a pa
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27 Jul 2018, 07:11
27 Jul 2018, 07:11
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Each term of a certain sequence is calculated by adding a particular constant to the previous term. The 2nd term of this sequence is 27 and the 5th term is 84. What is the 1st term of this sequence?
(A) 20
(B) 15
(C) 13
(D) 12
(E) 8
(A) 20
(B) 15
(C) 13
(D) 12
(E) 8
Re: Each term of a certain sequence is calculated by adding a pa
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12 Aug 2018, 05:26
12 Aug 2018, 05:26
Expert Reply
Explanation
Let k equal the constant added to a term to get the next term. If the second term = 27, then the third term = 27 + k, the 4th term = 27 + 2k, and the 5th term = 27 + 3k. The 5th term equals 84, so create an equation:
\(27 + 3k = 84\)
\(3k = 57\)
\(k = 19\)
To find the first term, subtract k from the second term. The first term \(= 27 – 19 = 8\).
Let k equal the constant added to a term to get the next term. If the second term = 27, then the third term = 27 + k, the 4th term = 27 + 2k, and the 5th term = 27 + 3k. The 5th term equals 84, so create an equation:
\(27 + 3k = 84\)
\(3k = 57\)
\(k = 19\)
To find the first term, subtract k from the second term. The first term \(= 27 – 19 = 8\).
Re: Each term of a certain sequence is calculated by adding a pa
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06 Nov 2021, 00:59
06 Nov 2021, 00:59
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