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Eight points lie on a circle.
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08 Feb 2022, 07:30
08 Feb 2022, 07:30
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Eight points lie on a circle.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of triangles you can make using 3 of the given points as vertices |
The number of pentagons you can make using 5 of the given points as vertices |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Eight points lie on a circle.
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08 Feb 2022, 07:43
08 Feb 2022, 07:43
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Carcass wrote:
Eight points lie on a circle.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of triangles you can make using 3 of the given points as vertices |
The number of pentagons you can make using 5 of the given points as vertices |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Every set of 3 vertices will create a triangle.
Quantity A = the number of ways to select 3 vertices from 8 vertices.
Since the order in which we select the vertices does not matter, we can use combinations.
We can select 3 vertices from 8 vertices in 8C3 ways.
Similarly, every set of 5 vertices will create a triangle.
Quantity B = the number of ways to select 5 vertices from 8 vertices.
We can select 5 vertices from 8 vertices in 8C5 ways.
Important: Rather than calculate 8C3 and 8C5, we can use the following property that says: nCr = nC(n-r).
For example 10C3 = 10C7, and 7C2 = 7C5
So, it must be the case that 8C3 = 8C5
Answer: C
gmatclubot
Eight points lie on a circle. [#permalink]
08 Feb 2022, 07:43
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