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Every week, Renee is paid $40 per hour for the first 40 hour

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sandy
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Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   25 Aug 2018, 15:28
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Every week, Renee is paid $40 per hour for the first 40 hours she works, and $80 per hour for each hour she works after the first 40 hours. How many hours would Renee have to work in one week to earn an average (arithmetic mean) of $60 per hour that week?

(A) 60
(B) 65
(C) 70
(D) 75
(E) 80
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amorphous
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   02 Sep 2018, 21:26
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For the first 40 hrs she earns $40 per hr hence she should work for the first 40 hrs. Her income on that would be $1600
For each hr more she will earn $80. Hence, let the extra hrs she works be x then for that she earns 80x.

By question, \(\frac{80x + 1600}{40+x} = 60\)
solve for x; x = 40
Therefore, total hrs she has to work for the week to earn $60 avg would be 80 hrs.
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   15 Oct 2018, 09:04
Renee makes $40*40 hours=$1600 in first 40 hours
Let 't' be the no of hours Renee would work.
Given, Renee makes $80 per hour for each hour she works after the first 40 hours. So, she makes an additional pay $80*(t-40)hours for every hour after 40 hours.

So, 1600+80(t−40)t=601600+80(t−40)t=60
Or, 1600+80t-3200=60t
Or, 20t=1600
or, t=80 hours

Ans. (E)
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   23 Oct 2018, 09:45
can the answer be D?
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   10 Jan 2019, 17:54
Hovsep wrote:
can the answer be D?

How please explain.
I think, may be not.
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   10 Jan 2019, 17:57
ruposh6240 wrote:
So, 1600+80(t−40)t=601600+80(t−40)t=60


I don't get it.
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   10 Jan 2019, 20:58
This is a select one multiple choice question there can be only 1 ans choice. Ans is D
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   11 Jul 2019, 03:00
amorphous wrote:
This is a select one multiple choice question there can be only 1 ans choice. Ans is D




The one and only answer here is E certainly.
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   11 Jul 2019, 03:05
ruposh6240 wrote:

Edited:

Let 't' = number of hours Renee will have to work.
Concept: The average rate Renee gets paid is equal to the total wages earned divided by the total number of hours worked.
Rene earns\($40\) per hour for the first \(40\) hours, so she makes\(40 × 40\)= \($1,600\) in the first \(40\) hours. She also earns\($80\) for every hour after 40 hours, for additional pay of\($80(t – 40)\). Therefore, her total pay can be calculated as:

So,\(\frac{1600+80(t−40)}{t}\)=\(60\)
Or, \(1600+80t-3200\)=\(60t\)
Or, \(20t\)=\(1600\)
or, \(t\)=\(80 hours\)

Ans. (E)
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   10 Sep 2021, 04:40
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Let, extra hours = x

(40*40 + 80*x) / (40+x) = 60
=> 1600 + 80*x = 2400 + 60*x
=> 20*x = 800
=> x = 40

So, in total = 40 + 40 = 80 (E)
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink] New post   28 Mar 2023, 20:46
Hello from the GRE Prep Club BumpBot!

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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
28 Mar 2023, 20:46
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