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Exactly 8 years ago, Jim’s son was twice as old as Jim’s
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17 Oct 2017, 22:25
17 Oct 2017, 22:25
00:00
Question Stats:
73% (01:19) correct
26% (02:25) wrong based on 15 sessions
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Exactly 8 years ago, Jim’s son was twice as old as Jim’s daughter. If Jim’s son is now 5 years older than his daughter, how old is Jim’s daughter now?
(A) 5
(B) 10
(C) 13
(D) 16
(E) 18
Kudos for correct solution.
(A) 5
(B) 10
(C) 13
(D) 16
(E) 18
Kudos for correct solution.
Re: Exactly 8 years ago, Jim’s son was twice as old as Jim’s
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18 Oct 2017, 05:15
18 Oct 2017, 05:15
1
Calling S son's age and D daughter's age, we get
\(S-8 = 2(D-8)\)
\(S = D+5\)
Solving, D = 13. Answer C
\(S-8 = 2(D-8)\)
\(S = D+5\)
Solving, D = 13. Answer C
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Re: Exactly 8 years ago, Jim’s son was twice as old as Jim’s
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08 Jan 2018, 10:51
08 Jan 2018, 10:51
Expert Reply
Bunuel wrote:
Exactly 8 years ago, Jim’s son was twice as old as Jim’s daughter. If Jim’s son is now 5 years older than his daughter, how old is Jim’s daughter now?
(A) 5
(B) 10
(C) 13
(D) 16
(E) 18
(A) 5
(B) 10
(C) 13
(D) 16
(E) 18
We can let Jim’s son’s current age = s and Jim’s daughter’s current age = d. We can also state that 8 years ago, his son was (s - 8) years old and his daughter was (d - 8) years old. We can create the following equation:
s - 8 = 2(d - 8)
s - 8 = 2d - 16
s = 2d - 8
and
s = 5 + d
Thus:
2d - 8 = 5 + d
d = 13
Answer: C
