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f(x) = 2x – 3 f(m) = –11 [#permalink]
Given that \(f(x) = 2x - 3\) and \(f(m) = -11\)

Quantity A = m

Let's find out the value of m
To find f(m) we need to replace x with m in f(x)
=> f(m) = 2m - 3 = -11 (given)
=> 2m = -11 + 3 = -8
=> m = -4

Quantity B = \(\frac{1}{2} f(m)\)
= \(\frac{1}{2}\) * -11 = \(\frac{-11}{2}\) = -5.5

Clearly, Quantity A (-4) > Quantity B(-5.5)

So, Answer will be A
Hope it helps!

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f(x) = 2x 3 f(m) = 11 [#permalink]
1
To compare the two quantities we need the value of m.

We know that \(f(m) = -11\)

We also know that \(f(x) = 2x-3\)

Combining both we get,

\(f(m) = 2m-3 = -11\)

\(2m-3 = -11\)

\(2m = -11+3\)

\(2m = -8\)

\(m = -8/2\)

\(m = 4\)

Quantity A = 4

Quantity B is \(1/2*f(m)\).

We know that \(f(m) = -11\)

Quantity B = \(-11/2 = -5.5\)

Quantity B = -5.5

Thus Quantity A is greatest.
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f(x) = 2x 3 f(m) = 11 [#permalink]
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