GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 28Live Online Class with Top GRE Expert Mike Butville
08:00 PM EDT
-10:00 PM EDT
Top scores are possible when you enroll in a powerful GRE course, taught live online + 6 months access to TTP GRE OnDemand video courses included! Class starts Mon/Wed Sept. 28, 2026 - Dec. 9, 2026, 8:00pm-10:00pm EST
f (x) = 2x + k and f (3) = 2k + 1
[#permalink]
04 Dec 2023, 00:48
04 Dec 2023, 00:48
1
Expert Reply
00:00
Question Stats:
86% (01:07) correct
13% (02:08) wrong based on 22 sessions
Hide Show timer Statistics
f (x) = 2x + k and f (3) = 2k + 1
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
k |
5 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Part of the project: The Butler-GRE Daily New Quant and Verbal Questions to Practice (2023) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
f (x) = 2x + k and f (3) = 2k + 1
[#permalink]
29 Jan 2024, 08:15
29 Jan 2024, 08:15
1
1
Bookmarks
We are given that
\(f(x) = 2x + k\)
\(f(3) = 6 + k\)
but we are also given
\(f(3) = 2k + 1\)
Equating both values for \(f(3)\)
\(2k + 1 = 6 + k\)
\(k=5\)
Quantity A
\(k=5\)
Quantity B
\(5\)
BOTH quantities are EQUAL.
The answer is C
\(f(x) = 2x + k\)
\(f(3) = 6 + k\)
but we are also given
\(f(3) = 2k + 1\)
Equating both values for \(f(3)\)
\(2k + 1 = 6 + k\)
\(k=5\)
Quantity A
\(k=5\)
Quantity B
\(5\)
BOTH quantities are EQUAL.
The answer is C
General Discussion
Manager
Joined: 11 Nov 2023
Posts: 228
Given Kudos: 78
WE:Business Development (Advertising and PR)
Re: f (x) = 2x + k and f (3) = 2k + 1
[#permalink]
04 Dec 2023, 21:30
04 Dec 2023, 21:30
1
Using the formula for f(x), \(f(3) = 2(3) + k = 6+k\)
We're also given that f(3) = 2k+1, so set these equal to each other:
\(6+k = 2k+1\)
\(5 = k\)
We're also given that f(3) = 2k+1, so set these equal to each other:
\(6+k = 2k+1\)
\(5 = k\)
