GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Fifteen candies are to be divided up among six children so
[#permalink]
20 Jul 2020, 05:08
20 Jul 2020, 05:08
1
Expert Reply
00:00
Question Stats:
80% (00:34) correct
20% (00:42) wrong based on 55 sessions
Hide Show timer Statistics
Fifteen candies are to be divided up among six children so that each child receives at least two candies.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The probability that any child receives six candies |
0 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: Fifteen candies are to be divided up among six children so
[#permalink]
20 Jul 2020, 05:08
20 Jul 2020, 05:08
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Re: Fifteen candies are to be divided up among six children so
[#permalink]
27 Jul 2020, 23:34
27 Jul 2020, 23:34
Six children receive atleast 2 candles. 6*2 = 12 candles.
We are left with 15-12 = 3 candles. If all 3 are given to ONE child, the child still has max 5 candles.
Hence, probability of a child getting 6 candles = 0. C.
We are left with 15-12 = 3 candles. If all 3 are given to ONE child, the child still has max 5 candles.
Hence, probability of a child getting 6 candles = 0. C.
