GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
For a certain event, 148 people attended. If all 148 had paid full adm
[#permalink]
06 Nov 2025, 04:38
06 Nov 2025, 04:38
Expert Reply
00:00
Question Stats:
64% (01:53) correct
35% (02:44) wrong based on 17 sessions
Hide Show timer Statistics
For a certain event, 148 people attended. If all 148 had paid full admission price, the total revenue would be three times the cost of sponsoring the event. (Admission price was the only source of revenue.)
As it happens, only 50 paid the full admission price, and the others paid nothing.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
As it happens, only 50 paid the full admission price, and the others paid nothing.
Quantity A |
Quantity B |
the total revenue |
the cost of sponsoring the event |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
- Part of the project: GRE Daily Quant Challenge - Topic-Wise 2025!!!
- Also replying to the unanswered questions
Re: For a certain event, 148 people attended. If all 148 had paid full adm
[#permalink]
10 Dec 2025, 10:09
10 Dec 2025, 10:09
Expert Reply
Let the full admission price be $p$ and the cost of sponsoring the event be $C$.
If all 148 paid, revenue would be $148 p$, and this equals three times the cost, so $\(148 p=3 C\)$, hence $\(C=\frac{148 p}{3}\)$.
Actual revenue is from only 50 people paying full price, so total revenue is $50 p$.
Compare $50 p$ with $\(C=\frac{148 p}{3}\)$ :
$$
\(\frac{50 p}{C}=\frac{50 p}{148 p / 3}=\frac{150}{148}>1\)
$$
So $\(50 p>C\)$, meaning Quantity A (total revenue) is greater than Quantity B (cost of sponsoring the event).
If all 148 paid, revenue would be $148 p$, and this equals three times the cost, so $\(148 p=3 C\)$, hence $\(C=\frac{148 p}{3}\)$.
Actual revenue is from only 50 people paying full price, so total revenue is $50 p$.
Compare $50 p$ with $\(C=\frac{148 p}{3}\)$ :
$$
\(\frac{50 p}{C}=\frac{50 p}{148 p / 3}=\frac{150}{148}>1\)
$$
So $\(50 p>C\)$, meaning Quantity A (total revenue) is greater than Quantity B (cost of sponsoring the event).
gmatclubot
Re: For a certain event, 148 people attended. If all 148 had paid full adm [#permalink]
10 Dec 2025, 10:09
Moderators:
