fdundo wrote:
I read about this concept on a blog :
To find the range of overlap -
1. Max overlap = 0.5
smaller of the 2 i.e smaller of 0.75 and 0.5
2. To find min overlap : P(AuB) = P(A) + P(B) - P(A and B)
[Using max value of P(AuB) as 1 to minmise P(A and B)]
Therefore, 1 = 0.75 + 0.5 - P(A and B)
=> P(A and B) = 0.25
Therefore, value has to lie between 0.25 and 0.5 i.e option C (1/3 = 0.33)
Does this make sense? Why cant we assume min overlap as 0 btw?
yes, the range of the probability can be from 0 to 1.
Here what is the probability of P (A) + P(B) = ? . This equals to 1.25, which is greater than 1
Meaning there is an overlap , so the minimum can't be zero