Carcass wrote:
For all integers \(n \neq 1\), let \(<n> = \frac{n+1}{n-1}\). Which of the following has the greatest value ?
A. <0>
B. <2>
C. <3>
D. <4>
E. <5>
In order to have the greatest value, the numerator must be maximum and the denominator must be minimum. Clearly, we can see that option B will give us the maximum value
We can also plug in the option choices;
A. \(<0> = \frac{0+1}{0-1} = -1\)
B. \(<2> = \frac{2+1}{2-1} = 3\)
C. \(<3> = \frac{3+1}{3-1} = 2\)
D. \(<4> = \frac{4+1}{4-1} = \frac{5}{3}\)
E. \(<5> = \frac{5+1}{5-1} = \frac{3}{2}\)