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Re: For any integer n greater than 1, [n denotes the product of [#permalink]
Given that [n denotes the product of all the integers from 1 to n, inclusive and we need to find how many prime numbers are there between [6 + 2 and [6 + 6, inclusive

[6 = Product of all the integers from 1 to 6, inclusive = 1*2*3*4*5*6 = 6!

[6 + 2 = 6! + 2 = 1*2*3*4*5*6 + 2 = 2*(1*3*4*5*6 + 1) = a Multiple of 2 => NOT a Prime Number
Similarly, 6! is also a multiple of all numbers from 3 to 6
=> all of the numbers from 6! + 2 to 6! + 6 will be Non-Prime numbers.

So, Answer will be A.
Hope it helps!

(Working below)

[6 + 3 = 6! + 3 = 1*2*3*4*5*6 + 3 = a Multiple of 3 => NOT a Prime Number
[6 + 4 = 6! + 4 = 1*2*3*4*5*6 + 4 = a Multiple of 4 => NOT a Prime Number
[6 + 5 = 6! + 5 = 1*2*3*4*5*6 + 5 = a Multiple of 5 => NOT a Prime Number
[6 + 6 = 6! + 6 = 1*2*3*4*5*6 + 6 = a Multiple of 6 => NOT a Prime Number

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Re: For any integer n greater than 1, [n denotes the product of [#permalink]
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