GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
For numbers p, q, and r, (p × q × r) < 0
[#permalink]
02 Dec 2018, 09:59
02 Dec 2018, 09:59
2
Expert Reply
7
Bookmarks
00:00
Question Stats:
61% (00:48) correct
38% (00:55) wrong based on 178 sessions
Hide Show timer Statistics
For numbers \(p\), \(q\), and \(r\), \((p * q * r) < 0\) and \(\frac{(p * q)^2}{r} < 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(p * q\) |
\(0\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
Re: For numbers p, q, and r, (p × q × r) < 0 and Magoosh; Lele,
[#permalink]
02 Dec 2018, 20:36
02 Dec 2018, 20:36
Answer: A
We have (p*q)^2 / r < 0. Since anything in power of 2 or any even is positive then as this expression is negative we can construe that r must be negative.
We have p*q*r <0 so either one or 3 of them are negative.
We know that r is negative. Two approaches are possible either r is negative and p&q are positive, then (p*q) is positive and The answer is A. Or the two of p&q are negative then (p*q) is again positive and bigger than 0, So, the answer is A.
We have (p*q)^2 / r < 0. Since anything in power of 2 or any even is positive then as this expression is negative we can construe that r must be negative.
We have p*q*r <0 so either one or 3 of them are negative.
We know that r is negative. Two approaches are possible either r is negative and p&q are positive, then (p*q) is positive and The answer is A. Or the two of p&q are negative then (p*q) is again positive and bigger than 0, So, the answer is A.
Re: For numbers p, q, and r, (p × q × r) < 0 and Magoosh; Lele,
[#permalink]
03 Dec 2018, 02:19
03 Dec 2018, 02:19
1
Expert Reply
Carcass wrote:
For numbers \(p\), \(q\), and \(r\), \((p * q * r) < 0\) and \(\frac{(p * q)^2}{r} < 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(p * q\) |
\(0\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
\(\frac{(p * q)^2}{r} < 0\)..
since \((p*q)^2\) is positive, r<0...
Now \(p*q*r<0.....(p*q)*r<0\)..
As we know r<0, \(p*q>0.....A>B\)
A
