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For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8,
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27 Aug 2020, 10:09
27 Aug 2020, 10:09
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For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8, the mean is how much greater than the median?
(A) 0
(B) 1
(C) n+l
(D) n+2
(E) n+3
(A) 0
(B) 1
(C) n+l
(D) n+2
(E) n+3
Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8,
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27 Aug 2020, 10:10
27 Aug 2020, 10:10
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
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Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8,
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27 Aug 2020, 10:37
27 Aug 2020, 10:37
Carcass wrote:
For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8, the mean is how much greater than the median?
(A) 0
(B) 1
(C) n+l
(D) n+2
(E) n+3
(A) 0
(B) 1
(C) n+l
(D) n+2
(E) n+3
To calculate the median, arrange the numbers in ascending order: {n, n + 1, n + 2, n + 4, n + 8}
Since we have an ODD number of values, the median is the middlemost term
Median = n + 2
The mean = [n + (n+1) + (n+2) + (n+4) + (n+8)]/5
= (5n + 15)/5
= n + 3
The mean is how much greater than the median?
Difference = (n + 3) - (n + 2)
= 1
Answer: B
Cheers,
Brent
