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Re: For the rectangular solid above, the square of the length of the diago [#permalink]
Expert Reply
specifically what you did not get ?
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Re: For the rectangular solid above, the square of the length of the diago [#permalink]
Carcass wrote:
specifically what you did not get ?

i have solved by using pythagorus theorem..And the answer is different..And this combined Square of all the three (xy)2=112+72+82=121+49+64=234
(
𝑥
𝑦
)
2
=
11
2
+
7
2
+
8
2
=
121
+
49
+
64
=
234

this step is what i didnt understood
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For the rectangular solid above, the square of the length of the diago [#permalink]
1
Expert Reply
It is just a matter of formula

Attachment:
GRE For the rectangular solid above.jpg
GRE For the rectangular solid above.jpg [ 21.98 KiB | Viewed 120 times ]


First find the diagonal of the rectangle which is the base of the entire solid (red line

\(11^2+7^2=121+49=\sqrt{170} \approx 13.03\)

Then find the diagonal with the same process using the diagonal (red line) + the height (blue line)

\(13.03^2+8^2=169.7+64 \approx 233.7 \)

Answer is 234

Two easy steps
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