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Forty tiles of dimensions 1 foot × 2 foot each are required
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16 May 2019, 16:25
16 May 2019, 16:25
Expert Reply
00:00
Question Stats:
73% (00:37) correct
26% (01:52) wrong based on 42 sessions
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Forty tiles of dimensions 1 foot × 2 foot each are required to completely cover a floor. How many tiles of dimensions 2 foot × 4 foot each would be required to completely cover the same floor?
(A) 10
(B) 20
(C) 80
(D) 160
(E) 320
(A) 10
(B) 20
(C) 80
(D) 160
(E) 320
Re: Forty tiles of dimensions 1 foot × 2 foot each are required
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13 May 2020, 06:13
13 May 2020, 06:13
Expert Reply
40 = 1*2 = 40*2 = 80 required
New area 2*4=8 :80;8=10
A is the answer
New area 2*4=8 :80;8=10
A is the answer
Re: Forty tiles of dimensions 1 foot × 2 foot each are required
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13 May 2020, 07:14
13 May 2020, 07:14
1
Area of floor = 40 * (1) * (2) = 40 * (2/2) * (4/2) = (40 * (2) * (4))/4 = 10 * (2) * (4)
So, we require 10 tiles.
So, we require 10 tiles.
