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Four people have an average (arithmetic mean) age of 18, and
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30 Aug 2018, 07:30
30 Aug 2018, 07:30
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Question Stats:
70% (01:13) correct
30% (01:04) wrong based on 160 sessions
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Four people have an average (arithmetic mean) age of 18, and none of the people are older than 30.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The range of the four people’s ages |
\(25\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: Four people have an average (arithmetic mean) age of 18, and
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03 Sep 2018, 05:21
03 Sep 2018, 05:21
I think ans is B
Re: Four people have an average (arithmetic mean) age of 18, and
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03 Sep 2018, 15:45
03 Sep 2018, 15:45
1
D
Since there's an upper limit of 30, the range is determined by the lowest age possible. We get this case when 2 people are 30, then the other 2 people have a combined age of 12. In the most extreme case, the lowest age is then 1, and then the range is 29, greater than 25, but in another extreme case, the other 2 people are both 6 so the range is 30-6=24 which is less than 25. So cannot be determined
Since there's an upper limit of 30, the range is determined by the lowest age possible. We get this case when 2 people are 30, then the other 2 people have a combined age of 12. In the most extreme case, the lowest age is then 1, and then the range is 29, greater than 25, but in another extreme case, the other 2 people are both 6 so the range is 30-6=24 which is less than 25. So cannot be determined
