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given a series 1,2,2,3,3,3,4,4,4,4... if this cintinues then
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10 Dec 2015, 20:33
10 Dec 2015, 20:33
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100% (01:14) correct
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given a series 1,2,2,3,3,3,4,4,4,4... if this continues then what will be the value of 100th term?
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Joined: 16 May 2014
Posts: 592
Given Kudos: 0
GRE 1: Q165 V161
Re: given a series 1,2,2,3,3,3,4,4,4,4... if this cintinues then
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11 Dec 2015, 00:17
11 Dec 2015, 00:17
Expert Reply
Even though the options are not given, the answer is 45.
This problem can be simplified in the following:
\(1 + 2 + 3 + .... + n >= 1000\)
\(or, (n)(n+1)/2 >= 1000\)
After some trials you have to find the n for which the LHS of the above equation just becomes larger than 1000. In this case n is 45. Thats the answer .
Explanation
This problem can be simplified in the following:
\(1 + 2 + 3 + .... + n >= 1000\)
\(or, (n)(n+1)/2 >= 1000\)
After some trials you have to find the n for which the LHS of the above equation just becomes larger than 1000. In this case n is 45. Thats the answer .
Re: given a series 1,2,2,3,3,3,4,4,4,4... if this cintinues then
[#permalink]
11 Dec 2015, 19:02
11 Dec 2015, 19:02
soumya1989 wrote:
Even though the options are not given, the answer is 45.
This problem can be simplified in the following:
\(1 + 2 + 3 + .... + n >= 1000\)
\(or, (n)(n+1)/2 >= 1000\)
After some trials you have to find the n for which the LHS of the above equation just becomes larger than 1000. In this case n is 45. Thats the answer .
Explanation
This problem can be simplified in the following:
\(1 + 2 + 3 + .... + n >= 1000\)
\(or, (n)(n+1)/2 >= 1000\)
After some trials you have to find the n for which the LHS of the above equation just becomes larger than 1000. In this case n is 45. Thats the answer .
but the ans says 14.
1,2,2,3,3,3,4,4,4,4,5,5,5,5,5,6,6,6,6,6,6,......................14,14,14,14,14,14,14,14,14,14,14,14,14,14
is there any formula?
