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Given equation of a line as x + y = 4
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01 Sep 2016, 07:23
01 Sep 2016, 07:23
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Given equation of a line as x + y = 4. What is the area of the triangle formed by the line with coordinate axis?
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Joined: 16 May 2014
Posts: 592
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GRE 1: Q165 V161
Re: Given equation of a line as x + y = 4
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01 Sep 2016, 07:49
01 Sep 2016, 07:49
Expert Reply
All we need to do is to find the base and height of the right angled triangle formed. The points are (0,0) and two other points one in x-axis and the other one in y-axis.
The point in x-axis is derived by putting y = 0 in the line equation:
x + y = 4
The point is (4,0) and the other point of y-axis similarly is (0,4). So the base of the triangle x-axis segment = 4 and the height of the triangle the y-axis segment is 4. Therefore the area,
A = 1/2 * 4*4 = 8 sq units.
The point in x-axis is derived by putting y = 0 in the line equation:
x + y = 4
The point is (4,0) and the other point of y-axis similarly is (0,4). So the base of the triangle x-axis segment = 4 and the height of the triangle the y-axis segment is 4. Therefore the area,
A = 1/2 * 4*4 = 8 sq units.
Re: Given equation of a line as x + y = 4
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20 Jul 2023, 10:55
20 Jul 2023, 10:55
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