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given figure is that of a regular hexagon. what is the area?
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30 Jan 2018, 00:05
30 Jan 2018, 00:05
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given figure is that of a regular hexagon. what is the area of the hexagon? Give your answer without the units
Show: ::
\(96*\sqrt{3}\)
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Re: given figure is that of a regular hexagon. what is the area?
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30 Jan 2018, 07:10
30 Jan 2018, 07:10
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amorphous wrote:
given figure is that of a regular hexagon. what is the area of the hexagon? Give your answer without the units
Show: ::
\(96*\sqrt{3}\)
Notice that we can divide a regular hexagon into 6 identical equilateral triangles
So, area of hexagon = 6(area of 1 equilateral triangle)
Useful formula: Area of equilateral triangle = (side²)(√3)/4
Since each side has length 8, we can write: Area of one equilateral triangle = (8²)(√3)/4
= (64)(√3)/4
= 16√3
So, area of hexagon = 6(area of 1 equilateral triangle)
= area of hexagon = 6(16√3)
= 96√3
Answer: 96√3
Cheers,
Brent
Re: given figure is that of a regular hexagon. what is the area?
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30 Jan 2018, 07:43
30 Jan 2018, 07:43
1
amorphous wrote:
given figure is that of a regular hexagon. what is the area of the hexagon? Give your answer without the units
Here we know
Area of Hexagon = \([3\sqrt{3} * (side)^2]\)\(/2\)
since side = 8
Therefore putting the value in the equation we get= \([3\sqrt{3} * (8)^2]\)\(/2\)
= \(96\sqrt{3}\)
