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GRE Math Challenge #120-x < y < z
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Updated on: 11 Aug 2018, 22:49
Updated on: 11 Aug 2018, 22:49
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Question Stats:
69% (00:43) correct
31% (00:34) wrong based on 100 sessions
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\(x < y < z\)
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
Quantity A |
Quantity B |
\(\frac{(x+y+z)}{3}\) |
\(z\) |
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
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Re: GRE Math Challenge #120
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17 May 2015, 09:26
17 May 2015, 09:26
2
sandy wrote:
\(x < y < z\)
Quantity A: (x+y+z)/3
Quantity B: z
Quantity A: (x+y+z)/3
Quantity B: z
Nice question!
IMPORTANT: Notice that (x+y+z)/3 is equal to the AVERAGE of x, y and z.
Since x < y < z, the average of these 3 values must be greater than x and less than z.
Since the average of the 3 values must be less than z, we can conclude that (x+y+z)/3 is definitely less than z
Answer:
Show: ::
B
Cheers,
Brent
Re: GRE Math Challenge #120-x < y < z
[#permalink]
11 Aug 2018, 11:51
11 Aug 2018, 11:51
1
sandy wrote:
\(x < y < z\)
Quantity A: (x+y+z)/3
Quantity B: z
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
Quantity A: (x+y+z)/3
Quantity B: z
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
x<y<z. we don't know whether they are consecutive or not. Even if they are consecutive average will always be lower than the highest numbers. So, z is greater.
The best answer is B.
