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GRE Math Challenge #122- In a certain city, 20ºF was
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Updated on: 20 Feb 2020, 14:36
Updated on: 20 Feb 2020, 14:36
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79% (00:39) correct
20% (00:24) wrong based on 44 sessions
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In a certain city, 20ºF was the average (arithmetic mean) of the low temperatures of xºF, 25ºF, and 37ºF on three consecutive days.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
x |
0 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: GRE Math Challenge #122
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18 May 2015, 11:06
18 May 2015, 11:06
1
sandy wrote:
In a certain city, 20ºF was the average (arithmetic mean) of the low temperatures of xºF, 25ºF, and 37ºF on three consecutive days.
Quantity A: x
Quantity B: 0
Quantity A: x
Quantity B: 0
If the mean of the THREE values is 20 degrees, then we can write: (x + 25 + 37)/3 = 20
To solve for x, first multiply both sides of the equation by 3 to get: x + 25 + 37 = 60
Simplify: x + 62 = 60
Solve: x = -2
So, we get:
Quantity A: -2
Quantity B: 0
Answer:
Show: ::
B
Cheers,
Brent
Re: GRE Math Challenge #122- In a certain city, 20ºF was
[#permalink]
19 Feb 2022, 02:12
19 Feb 2022, 02:12
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