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GRE Math Challenge #132- x + y + n = 15 x + y + k = 9

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sandy
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GRE Math Challenge #132- x + y + n = 15 x + y + k = 9 [#permalink] New post   Updated on: 20 Feb 2020, 16:10
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\(x + y + n = 15\)

\(x + y + k = 9\)

Quantity A
Quantity B
\(n-k\)
\(6\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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C

Originally posted by sandy on 15 May 2015, 11:35.
Last edited by Carcass on 20 Feb 2020, 16:10, edited 1 time in total.
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GreenlightTestPrep
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Re: GRE Math Challenge #132 [#permalink] New post   17 May 2015, 08:39
1
sandy wrote:
x + y + n = 15
x + y + k = 9

Quantity A: n – k
Quantity B: 6


We need to recognize that, if we subtract the bottom equation from the top equation, something nice happens. We get:

(x + y + n) - (x + y + k) = 15 - 9
Simplify: n - k = 6

So, we get:
Quantity A: 6
Quantity B: 6

Answer:
Show: ::
C


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Brent
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Re: GRE Math Challenge #132- x + y + n = 15 x + y + k = 9 [#permalink] New post   28 Sep 2020, 08:57
1
When a question asks us to find the value of (n-k), we try to find the value of (n-k) by manipulating the equations. Trying to find n and k separately and then finding n-k is a very common trap that one can get into. If you thought like this, you were probably wondering how you could find out the values of n and k when there are fewer equations than unknowns.

x+y+n = 15
x+y+k = 9.

Subtracting the second equation from the first, we have n-k = 6.

So, there is no need to find out n and k to compute n-k.

Quantity A is equal to Quantity B.
Correct answer is option C.
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gmatclubot
Re: GRE Math Challenge #132- x + y + n = 15 x + y + k = 9 [#permalink]
28 Sep 2020, 08:57
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