Last visit was: 27 Dec 2024, 04:12 It is currently 27 Dec 2024, 04:12

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
User avatar
Retired Moderator
Joined: 07 Jun 2014
Posts: 4815
Own Kudos [?]: 11274 [3]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12238 [0]
Given Kudos: 136
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12238 [0]
Given Kudos: 136
Send PM
Intern
Intern
Joined: 25 Jun 2022
Posts: 17
Own Kudos [?]: 8 [0]
Given Kudos: 3
Send PM
Re: GRE Math Challenge #137- (x+y) and 2(x+y) [#permalink]
What's wrong with dividing both sides by (x+y)? If we do so, Quantity B (2) will always be greater than A (1).
Verbal Expert
Joined: 18 Apr 2015
Posts: 30515
Own Kudos [?]: 36880 [0]
Given Kudos: 26112
Send PM
Re: GRE Math Challenge #137- (x+y) and 2(x+y) [#permalink]
Expert Reply
TAYYABGRE wrote:
What's wrong with dividing both sides by (x+y)? If we do so, Quantity B (2) will always be greater than A (1).



Brent explained WHY we cannot beautifully above. Please read Sir

Essentially, we cannot because we DO NOT know the values of x and y
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12238 [2]
Given Kudos: 136
Send PM
Re: GRE Math Challenge #137- (x+y) and 2(x+y) [#permalink]
2
TAYYABGRE wrote:
What's wrong with dividing both sides by (x+y)? If we do so, Quantity B (2) will always be greater than A (1).


Whenever you divide both sides by an unknown quantity such as x+y, you are risking the possibility of that x+y equals 0 or some negative value.

This video explains this concept in much greater detail: https://www.greenlighttestprep.com/modu ... video/1097
Intern
Intern
Joined: 25 Jun 2022
Posts: 17
Own Kudos [?]: 8 [0]
Given Kudos: 3
Send PM
GRE Math Challenge #137- (x+y) and 2(x+y) [#permalink]
Thank you so much.
Prep Club for GRE Bot
GRE Math Challenge #137- (x+y) and 2(x+y) [#permalink]
Moderators:
GRE Instructor
88 posts
GRE Forum Moderator
37 posts
Moderator
1115 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne