fabiha22 wrote:
what if repetition was allowed ? would the formulae be still used ?
when repetitions are allowed process will be different
no of 4 letter password =
6 6 6 6=\(6^4\) (each position can be filled with 6 letters)
no of 5 letter password =
6 6 6 6 6=\(6^5\) (each position can be filled with 6 letters)
no of 6 letter password =
6 6 6 6 6 6=\(6^6\) (each position can be filled with 6 letters)
total number of passwords are =\(6^4\)+\(6^5\) +\(6^6\)
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thank you
gajala
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