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GRE Math Challenge #26-O is the center of the circle
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Updated on: 14 Apr 2020, 14:21
Updated on: 14 Apr 2020, 14:21
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Question Stats:
54% (01:10) correct
45% (00:57) wrong based on 114 sessions
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O is the center of the circle, & ROS is a right triangle
Quantity A |
Quantity B |
\(\frac{PQ}{RS}\) |
\(\frac{2}{1}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: GRE Math Challenge #26-O is the center of the circle
[#permalink]
08 Mar 2018, 01:05
08 Mar 2018, 01:05
3
sandy wrote:
O is the center of the circle, & ROS is a right triangle
Column A: PQ/RS
Column B: 2/1
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
We should know that ROS is isolesces right triganle since OR and OS are radius with the same length which assume to be 1.
then RS=\(\sqrt{2}\)
For qaunt A, PQ=diameter=2 and PQ/RS=\(\frac{2}{\sqrt{2}}\)
and since \(\sqrt{2}\) are bigger than 1, we can deduce that B>A
Re: GRE Math Challenge #26-O is the center of the circle
[#permalink]
14 Apr 2020, 14:22
14 Apr 2020, 14:22
Expert Reply
Bump for further discussion
