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Joined: 16 May 2014
Posts: 592
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GRE 1: Q165 V161
GRE Math Challenge #41- If x is an integer
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Updated on: 22 Feb 2020, 09:09
Updated on: 22 Feb 2020, 09:09
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Question Stats:
51% (00:51) correct
48% (00:52) wrong based on 277 sessions
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x is an integer.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(|23x|\) |
\(2 \sqrt{x^2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Originally posted by soumya1989 on 28 Feb 2015, 02:57.
Last edited by GreenlightTestPrep on 22 Feb 2020, 09:09, edited 3 times in total.
Last edited by GreenlightTestPrep on 22 Feb 2020, 09:09, edited 3 times in total.
Updated
Re: GRE Math Challenge #41- If x is an integer
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11 Mar 2018, 05:09
11 Mar 2018, 05:09
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soumya1989 wrote:
If x is an integer, what is the value of x?
A. Column A is prime
B. Column B is prime
C. Column A & B both are prime
D. Column A & B both are NOT prime
E. Cannot be determined
| Column A | Column B |
| \(|23x|\) | \(2\sqrt{x^2}\) |
A. Column A is prime
B. Column B is prime
C. Column A & B both are prime
D. Column A & B both are NOT prime
E. Cannot be determined
We are told that x is an integer. Thus, we can sex x as 0. Then, for quant A, |23X|would be 0.
For quant B, \(2\sqrt{x^2}\) would be 0, as well.
YET, if we set x=1. Then for Quant A, |23X|would be 23. For quant B, \(2\sqrt{x^2}\) would be 2.
Hence, the ans wouldm be D.
Re: GRE Math Challenge #41- If x is an integer
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18 Feb 2020, 13:10
18 Feb 2020, 13:10
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