Last visit was: 23 Nov 2024, 18:08 It is currently 23 Nov 2024, 18:08

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
User avatar
Director
Director
Joined: 16 May 2014
Posts: 592
Own Kudos [?]: 2047 [9]
Given Kudos: 0
GRE 1: Q165 V161
Send PM
avatar
Intern
Intern
Joined: 02 Jun 2014
Posts: 2
Own Kudos [?]: 6 [4]
Given Kudos: 0
Send PM
User avatar
Director
Director
Joined: 16 May 2014
Posts: 592
Own Kudos [?]: 2047 [0]
Given Kudos: 0
GRE 1: Q165 V161
Send PM
avatar
Intern
Intern
Joined: 02 Sep 2015
Posts: 1
Own Kudos [?]: 0 [0]
Given Kudos: 0
Send PM
Re: GRE Math Challenge #51 [#permalink]
The answer is C.
The question is sum of all possible values of x. That means 3+(-2)=1
avatar
Intern
Intern
Joined: 11 Sep 2015
Posts: 4
Own Kudos [?]: 2 [1]
Given Kudos: 0
Send PM
Re: GRE Math Challenge #51 [#permalink]
1
Answer is C

If you put -2 in place of x you get +ve value in fourth root.
avatar
Intern
Intern
Joined: 06 Jul 2020
Posts: 8
Own Kudos [?]: 3 [0]
Given Kudos: 0
Send PM
Re: GRE Math Challenge #51-Then the sum of all possible solution [#permalink]
I can't post URLs yet, but if you type "graph of 4th root of (x^3 + 6*x^2)" into Google, it will show you the graph of the function.

The graph of (x^3+6*x^2)^(1/4) shows that x can in fact be negative, the only condition that holds is that x >= -6.

This follows from the inequality x^3+6*x^2 >= 0.
So x^2*(x+6)>= 0, therefore x+6 >= 0, therefore x >= -6

Therefore, the answer should be C, as possible roots of x include 0, 3, and -2 since -2 >= 6.

Am I missing something here?
avatar
Intern
Intern
Joined: 07 Sep 2020
Posts: 15
Own Kudos [?]: 1 [0]
Given Kudos: 0
Send PM
Re: GRE Math Challenge #51-Then the sum of all possible solution [#permalink]
when we put x=-2 we get x=2 ie is + ,so c
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5043
Own Kudos [?]: 74 [0]
Given Kudos: 0
Send PM
Re: GRE Math Challenge #51-Then the sum of all possible solution [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
Re: GRE Math Challenge #51-Then the sum of all possible solution [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne