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GRE Math Challenge #99- (3/5) + (2/3) or 1
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09 May 2015, 11:17
09 May 2015, 11:17
Expert Reply
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Question Stats:
87% (00:21) correct
12% (00:16) wrong based on 91 sessions
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Quantity A: (3/5) + (2/3)
Quantity B: 1
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
Quantity B: 1
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: GRE Math Challenge #99- (3/5) + (2/3) or 1
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27 Feb 2018, 08:16
27 Feb 2018, 08:16
sandy wrote:
Quantity A: (3/5) + (2/3)
Quantity B: 1
Quantity B: 1
One option is to replace the fractions with decimal equivalents
GIVEN:
Quantity A: (3/5) + (2/3)
Quantity B: 1
3/5 = 0.6 and 2/3 ≈ 0.66
So, we get:
Quantity A: 0.6 + 0.66
Quantity B: 1
Evaluate:
Quantity A: 1.26
Quantity B: 1
Quantity A is greater
Answer: A
Cheers,
Brent
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: GRE Math Challenge #99- (3/5) + (2/3) or 1
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27 Feb 2018, 08:19
27 Feb 2018, 08:19
1
sandy wrote:
Quantity A: (3/5) + (2/3)
Quantity B: 1
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
Quantity B: 1
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
Another approach is to ADD THE FRACTIONS
3/5 + 2/3 = 9/15 + 10/15 [I rewrote the fractions with common denominators]
= 19/15
= 1 4/15
So, we have:
Quantity A: 1 4/15
Quantity B: 1
Quantity A is greater
Answer: A
Cheers,
Brent
