This is part of our
GRE Math Essentials project is the best complement to our
Official GRE Quant Book. It provides a cuttingedge, indepth overview of all the math concepts to achieve 170 in the Quantitative Reasoning portion of the GRE. The book still remains our hallmark. However, the following chapters will give you a lot of tips, tricks, and shortcuts to make your quant preparation more robust and solid.
Source for some of the images in this post:
A Maths Dictionary for Kids by © Jenny Eather
1) Types of numbersNote \(\sqrt{negative numbers}\) or \(\frac{number}{0zero}\) are
NOT real !!
On the GRE by default, any number mentioned in the quant section is a
real number so must NOT assume that it is an integer unless stated clearly
2) Number Line3) Basic operations on numberssource:
http://www.amathsdictionaryforkids.com/Multiplication table4) Place and Face Value
Place Value  Face Value 
Place value is the value represented by a digit in a number according to its position in the number.  Face value is the actual value of a digit in a number. 
To get the place value of a number, we multiply the digit value with its numerical value. For example, in the number 452, the place value of 5 is (5 × 10) = 50, since 5 is in tens place.  The face value of a digit is the number itself. For example, in the number 452, the face value of 4 is 4. 
The place value of a number depends upon the position of the digit in the number.  The face value is independent of the position of the digit in the number. 
The place value of a digit in ones place is always a single digit and the place value of every next digit to the left increases by one more digit.  The face value of a number is always a single digit. 
source:
https://pkdeveloper.in/differencebetwe ... e%20number.
5) Basic operation on Even and Odd Numbers
Basic operation on Even and Odd Numbers 
Math operations
 Application
 Examples

Addition/Subtraction  Even \(\pm\) Even = Even; Odd \(\pm\) Odd = Even; Even \(\pm\) Odd = Odd
  8+4=6;Even
 9+5=14;Even
 7+2=9;Odd

Multiplication  Even \(\times\) Even = Even; Odd \(\times\) Odd = Odd; Even \(\times\) Odd = Even
Multiply ODD \(\times\) ODD = ALWAYS ODD.
  8 * 2=16;Even
 5 * 10 =50;Even
 3* 7 =21;Odd

Division  The division could lead us to a whole result (EVEN or ODD whole number) OR we could have a remainder
Odd / Odd = Odd; Even / Odd = Even; Odd / Even = Not divisible; Even / Even = Even or Odd  15/3=5; Odd 20/5=4; Even 13/2=? Not divisible 6/3=2; Even 25/5=5; Odd

6) Prime NumbersA number greater than 1 which has no factor other than 1 and the number itself is a
Prime NumberA number with two distinct factors.
We do have infinite prime numbers and apparently, to our knowledge today, there is NO clear pattern in their unfolding toward the infinite on the number line.
Prime numbers are only positive.
Two (2) is the oNLy positive Even prime numbers
The difference between any two primes greater than 2 is always even.
Verifying the primality (checking whether the number is a prime) of a given number \(n\) can be done by trial division, that is to say dividing \(n\) by all integer numbers smaller than \(\sqrt{n}\), thereby checking whether \(n\) is a multiple of \(m\leq{\sqrt{n}}\).
Example: Verifying the primality of \(161\): \(\sqrt{161}\) is little less than \(13\), from integers from \(2\) to \(13\), \(161\) is divisible by \(7\), hence \(161\) is not prime.
Note that, it is only necessary to try dividing by
prime numbers up to \(\sqrt{n}\), since if
n has any divisors at all (besides 1 and
n), then it must have a prime divisor.
If \(n\) is a positive integer greater than 1, then there is always a prime number \(p\) with \(n < p < 2n\).
7) RoundingRounding Rules
more than 5 > up
less than 5 < down
~ for decimal fractions
1. Look at the digit in the place value to be rounded to.
2. Increase it by 1 if the digit to the right of it is 5 or more.
3. Leave it the same if the digit to the right of it is less than 5.
4. Remove everything to the right of the digit.
Example:
Round 625.475 to 1 decimal place: 625.475 ≈ 625.5
~
when rounding to 10 or above there's an important change to step 4.4. Replace whole numbers to the right of the digit with zero(s), then remove everything to their right.
Examples:
Round 625.475 to 10: 625.475 ≈ 630
Round 625.475 to 100: 625.475 ≈ 600
8) P.E.M.D.A.S9) Divisibility Rules 1. A number is divisible by 2 if its unit’s digit is even or zero e.g. 128, 146, 34 etc.
2. A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 102, 192, 99 etc.
3. A number is divisible by 4 when the number formed by last two right hand digits is divisible by ‘4’ e.g. 576, 328, 144 etc.
4. A number is divisible by 5 when its unit’s digit is either five or zero : e.g. 1111535, 3970, 145 etc.
5. A number is divisible by 6 when it’s divisible by 2 and 3 both. e.g. 714, 509796, 1728 etc.
6. A number is divisible by 8 when the number formed by the last three right hand digits is divisible by ‘8’. e.g. 512, 4096, 1304 etc.
7. A number is divisible by 9 when the sum of its digits is divisible by 9 e.g. 1287, 11583, 2304 etc.
8. A number is divisible by 10 when its units digit is zero. e.g. 100, 170, 10590 etc.
9. A number is divisible by 11 when the difference between the sums of digits in the odd and even places is either zero or a multiple of 11. e.g. 17259, 62468252, 12221 etc.
For the number 17259 : Sum of digits in even places = 7 + 5 = 12, Sum of digits in the odd places = 1 + 2 + 9 =12 Hence 12 – 12 = 0.
10. A number is divisible by 12 when it is divisible by 3 & 4 both. e.g. 672, 8064 etc.
11. A number is divisible by 25 when the number formed by the last two Right hand digits is divisible by 25. e.g. 1025, 3475, 55550 etc.
12. A number is divisible by 125, when the number formed by last three right hand digits is divisible by 125. e.g. 2125, 4250, 6375 etc.
NOTE :
1. When any number with even number of digits is added to its reverse, the sum is always divisible by 11. e.g. 2341 + 1432 = 3773 which is divisible by 11.
2. If X is a prime number then for any whole number “a” \((a^X – a)\) is divisible by X e.g. Let X = 3 and a = 5. Then according to our rule \(5^3– 5\) should be divisible by 3.
Now \((5^3– 5) = 120\) which is divisible by 3
10) FactorsFactor• a whole number that divides exactly into another number.
• a whole number that multiplies with another number to make a third number.
Factors Pair
• a pair of numbers multiplied together form another number called their product.
Number of factorsA number N can be written as \( N=p^xq^yr^z\), where p,q, and r are prime factors of the number N, and x,y, and z are positive integers.
Number of factors : (including 1 and the number itself)\(=(x+1)(y+1)(z+1)\);
Sum of all the factors\(\left[ \begin{array}{ccr} \frac{a^{x+1}1}{a1} \end{array} \right]\) \(\left[ \begin{array}{ccr} \frac{b^{y+1}1}{b1} \end{array} \right]\) \(\left[ \begin{array}{ccr} \frac{c^{z+1}1}{c1} \end{array} \right]\)
Product all the factors\(N^{\frac{number of factors}{2}}\)
Suppose 120 is our number and the prime factorization is \(2^3*3^1*5^1\)
1) Number of factors: simply take the exponent of each factor and add 1. \((3+1)*(1+1)*(1+1)=16\)
2) Sum of all factors: \(\frac{[(2^0+2^1+2^2+2^3)(3^0+3^1)(5^0+5^1)]}{[(21) (31)(51)]} = 45\)
3) Product of all factors: \(120^{\frac{16}{2}}=120^8\)
11) Perfect Square NumbersA perfect square number is a nonnegative integer that can be expressed as the product of an integer with itself. I.E., a number that is a square of any integer is called a Perfect Square number. Perfect square numbers are always nonnegative.
Unit's digit  0  1  4  5  6  9 
Ten's digit  0  even  even  2  odd  even 
Some properties of a perfect square:
 Perfcet square number ALWAYS has even number of powers of prime factors;
 The number of distinct factors of a perfect square number is ALWAYS odd. (By factors we refer to only the "positive numbers that divide the number withouth remainder);
 The sum of distinct factors of a perfect square number is ALWAYS odd;
 A percet square number ALWAYS has an odd number of oddfactors, and even number of evenfactors;
Question to practice about perfect squarehttps://gre.myprepclub.com/forum/ifaperf ... tml#p59618https://gre.myprepclub.com/forum/aperfect ... tml#p32573https://gre.myprepclub.com/forum/positive ... tml#p39436https://gre.myprepclub.com/forum/aperfect ... tml#p5102912) Multiples13) HCF (GCD / GCF) & LCM OF NUMBERSHCF : It is the greatest factor common to two or more given numbers. It is also called GCF OR GCD (greatest common factor or greatest common divisor). e.g. HCF of 10 & 15 = 5, HCF of 55 & 200 = 5, HCF of 64 & 36 = 4
To find the HCF of given numbers, resolve the numbers into their prime factors and then pick the common term(s) from them and multiply them if more than one. This is the required HCF.
LCM : Lowest common multiple of two or more numbers is the smallest number which is exactly divisible by all of them. e.g. LCM of 5, 7, 10 = 70, LCM of 2, 4, 5 = 20, LCM of 11, 10, 3 = 330
To find the LCM resolve all the numbers into their prime factors and then pick all the quantities (prime factors) but not more than once and multiply them. This is the LCM.
NOTE:
1. LCM x HCF = Product of two numbers (valid only for “two”)
2. HCF of fractions = HCF of numerators ÷ LCM of denominators
3. LCM of fractions = LCM of numerators ÷ HCF of denominators
Calculating LCM :
Method 1 :
Factorization MethodRule – After expressing the numbers in terms of prime factors, the LCM is the product of highest powers of all factors.
Q. Find the LCM of 40, 120, 380.
A. 4\(0 = 4 \times 10 = 2 \times 2 \times 2 \times 5 = 2^3 \times 5^1\)
\(120 = 4 \times 30 = 2 \times 2 \times 2 \times 5 \times 3 = 2^3 \times 5^1 \times 3^1\)
\(380 = 2 \times 190 = 2 \times 2 \times 95 = 2 \times 2 \times 5 \times 19 = 2^2 \times 5^1 \times 19^1\)
⇒ Required LCM = \(2^3 \times 5^1 \times 3^1 \times 19^1 = 2280\).
Method 2 :
Division methodQ. Find the LCM of 6, 10, 15, 24, 39
Ans. LCM = 2 x 2 x 3 x 5 x 2 x 13 = 1560.
Calculating HCF FactorizationAfter expressing the numbers in term of the prime factors, the HCF is product of COMMON factors.
Ex. Find HCF of 88, 24, 124
\(88 = 2 \times 44 = 2 \times 2 \times 22 = 2 \times 2 \times 2 \times 11 = 2^3 \times 11^1\)
\(24 = 2 \times 12 = 2 \times 2 \times 6 = 2 \times 2 \times 2 \times 3 = 2^3 \times 3^1\)
\(124 = 2 \times 62 = 2 \times 2^1 \times 31^1 = 2^2 \times 31^1 ⇒ HCF = 2^2\)
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