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Re: GRE Practice Question-If b= 0 and a/b >0 [#permalink]
Good catch!
I've edited my solution accordingly.

Cheers,
Brent
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Re: GRE Practice Question-If b= 0 and a/b >0 [#permalink]
1
huda wrote:
GreenlightTestPrep wrote:
Osira wrote:
If b ≠ 0 and \(\frac{a}{b}\) > 0, then which of the following must be true?

A. a > b
B. b > 0
C. ab > 0


The question asks "What MUST be true?"
So, if we can find a case in which a statement is NOT true, we can eliminate it.

A. a > b
We're told that a/b > 0
So, it COULD be the case that a = 1 and b = 2 (since 1/2 > 0)
If a = 1 and b = 2, then the statement that a > b is NOT TRUE
ELIMINATE A

B. b > a
We're told that a/b > 0
So, it COULD be the case that a = 3 and b = 2 (since 3/2 > 0)
If a = 3 and b = 2, then the statement that b > a is NOT TRUE
ELIMINATE B

C. ab > 0
We're told that a/b > 0, which means EITHER a and b are both positive OR a and b are both negative
If a and b are both positive, then ab > 0
If a and b are both negative, then ab > 0
In BOTH possible cases ab > 0, which means statement C MUST be true.

Answer: C

Cheers,
Brent



Actually !!!!!

B. b > 0, not b > a, that you get to solve.



--------------------------------------
sandy wrote:
If \(x^2 - y^2 = 0\) and \(xy \neq 0\), which of the following MUST be true?
Indicate all such statements.

A. x = y
B. |x| = |y|
C. \(\frac{x^2}{y^2}=1\)


In the above example, if we are allowed to take different numbers for the value of a and b, we must take them here too. If so, then why don't we eliminate the answer choice B. here? I'm so confused.

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Re: GRE Practice Question-If b= 0 and a/b >0 [#permalink]
For these kinds of questions, you can try different pairs of values for each statement.
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Re: GRE Practice Question-If b= 0 and a/b >0 [#permalink]
GreenlightTestPrep wrote:
For these kinds of questions, you can try different pairs of values for each statement.


To be better if it has an explanation
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Re: GRE Practice Question-If b= 0 and a/b >0 [#permalink]
Expert Reply
No need ti pick numbers. Just think fundamental rules

For \(\frac{a}{b} > 0\) the two numbers, a and b, must be or both positive or both negative. So clearly the problem is NOT if a is > of be or vice-versa. This is a question to test and about signs.

So a could be or not true. However, the question is a must be true question.

A is out.

B > 0 ? could be positive or negative. Out

C is true. Is the only correct choice because \(minus \times minus\) OR \(plus \times plus\)= always the result is \(> 0\)
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Re: GRE Practice Question-If b= 0 and a/b >0 [#permalink]
thanks for sharing!
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Re: GRE Practice Question-If b= 0 and a/b >0 [#permalink]
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