Carcass wrote:
How many different four-letter words can be formed (the words need not be meaningful) using the letters of the word GREGARIOUS such that each word starts with G and ends with R?
(A) 8P2
(B) 8P22!∗2!
(C) 8P4
(D) 8P42!∗2!
(E) 10P22!∗2!
Place one G in the first slot and one R in the last slot:
G __ __ R
The remaining letters, {G, R, E, A, I, O, U, S}, can be arranged in the remaining 2 slots in
8P2 [no
indistinguishable(same) objects nor repetition]. The answer is
(A).
Note: Since the two G’s in the base word are indistinguishable, the word G 1 G 2 AR is the same as G 2 G 1 AR. Hence, the internal arrangement of the G’s or, for the same reason, the R’s is not important.