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How many liters of pure alcohol must be added to a 90-liter solution t
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16 Nov 2023, 02:23
16 Nov 2023, 02:23
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50% (02:35) wrong based on 8 sessions
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How many liters of pure alcohol must be added to a 90-liter solution that is 20 percent alcohol in order to produce a solution that is at least 25 percent alcohol?
Indicate all possible values.
(A) 4.5
(B) 5.0
(C) 5.5
(D) 6.0
(E) 6.5
Indicate all possible values.
(A) 4.5
(B) 5.0
(C) 5.5
(D) 6.0
(E) 6.5
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Re: How many liters of pure alcohol must be added to a 90-liter solution t
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01 Dec 2023, 13:09
01 Dec 2023, 13:09
1
The volume of alcohol in a solution = volume of solution * concentration of solution.
The current volume of alcohol = 90 * 0.20 = 18 liters.
Let x be the amount of pure alcohol to be added. We know that the final concentration is at least 0.25%. We can set up the equation as
\(\frac{(18+x)}{(90+x)} ≥ 0.25\)
Solving for this equation, we get \(x ≥ 6\). Since both 6.0 and 6.5 are equal to or greater than 6, the answers are D and E.
The current volume of alcohol = 90 * 0.20 = 18 liters.
Let x be the amount of pure alcohol to be added. We know that the final concentration is at least 0.25%. We can set up the equation as
\(\frac{(18+x)}{(90+x)} ≥ 0.25\)
Solving for this equation, we get \(x ≥ 6\). Since both 6.0 and 6.5 are equal to or greater than 6, the answers are D and E.
gmatclubot
Re: How many liters of pure alcohol must be added to a 90-liter solution t [#permalink]
01 Dec 2023, 13:09
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