GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If k is different from zero
[#permalink]
31 Oct 2022, 03:23
31 Oct 2022, 03:23
Expert Reply
00:00
Question Stats:
83% (00:46) correct
16% (01:44) wrong based on 12 sessions
Hide Show timer Statistics
If k is different from zero and \(\frac{(k^3 \times k \times k^4)^2}{k^n \times k}=k^{14}\), then n =
A. -1
B. 1
C. 3
D. 49
E. 129
A. -1
B. 1
C. 3
D. 49
E. 129
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: If k is different from zero
[#permalink]
07 Nov 2022, 12:00
07 Nov 2022, 12:00
1
Carcass wrote:
I k is different from zero and \(\frac{(k^3 \times k \times k^4)^2}{k^n \times k}=k^{14}\), then n =
A. -1
B. 1
C. 3
D. 49
E. 129
A. -1
B. 1
C. 3
D. 49
E. 129
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
\(\frac{(k^3 \times k \times k^4)^2}{k^n \times k}=k^{14}\)
Use property: \((x^a)(x^b) = x^{a+b}\)
So, \((k^3)(k)(k^4) = k^{3+1+4} = k^8\)
Now, \(\frac{(k^8)^2}{(k^n)(k)}=k^{14}\)
\(\frac{k^{16}}{(k^n)(k)}=k^{14}\)
\(\frac{k^{15}}{k^n}=k^{14}\)
n has to be 1
Hence, option B
gmatclubot
Re: If k is different from zero [#permalink]
07 Nov 2022, 12:00
Moderators:
