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If |1 – x| = 6 and |2y – 6| = 10, which of the following co
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23 Jul 2018, 09:57
23 Jul 2018, 09:57
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If |1 – x| = 6 and |2y – 6| = 10, which of the following could be the value of xy?
Indicate all such values.
A. –40
B. –14
C. –10
D. 56
Indicate all such values.
A. –40
B. –14
C. –10
D. 56
Re: If |1 – x| = 6 and |2y – 6| = 10, which of the following co
[#permalink]
24 Jul 2018, 20:03
24 Jul 2018, 20:03
2
Carcass wrote:
If |1 – x| = 6 and |2y – 6| = 10, which of the following could be the value of xy?
Indicate all such values.
A. –40
B. –14
C. –10
D. 56
Indicate all such values.
A. –40
B. –14
C. –10
D. 56
when dealing with modulus we have asses both the option.
1. positive case:
1 -x = 6
-x = 5
x= -5
2. negative case
-1 + x = 6
x = 7.
3. positive case .
2y - 6 = 10
y = 8
4. negative case .
-2y + 6 = 10
y = -2.
So , we will have 4 sets of values of xy.
1. -5 *8 =-40
2. -5 * -2 = 10
3. 7*8 =56
4 7* -2 = -14
So, the correct answer is a,b,d.
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If |1 x| = 6 and |2y 6| = 10, which of the following co
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01 Jul 2025, 03:41
01 Jul 2025, 03:41
1
↧↧↧ Detailed Video Solution to the Problem ↧↧↧
|1 - x| = 6
=> 1 - x = 6 or 1 - x = -6
=> x = 1-6 or x = 1 + 6
=> x = -5 or x = 7
|2y - 6| = 10
=> |y - 3| = 5
=> y - 3 = 5 or y - 3 = -5
=> y = 3 + 5 or y = 3 - 5
=> y = 8 or -2
=> Possible values of xy are
=> Possible values of xy are -40, -14, 10, 56
=> All options are possible
So, Answer will be A,B,D
Hope it helps!
Watch the following video to MASTER Absolute Values
|1 - x| = 6
=> 1 - x = 6 or 1 - x = -6
=> x = 1-6 or x = 1 + 6
=> x = -5 or x = 7
|2y - 6| = 10
=> |y - 3| = 5
=> y - 3 = 5 or y - 3 = -5
=> y = 3 + 5 or y = 3 - 5
=> y = 8 or -2
=> Possible values of xy are
- x = -5, y = 8, xy = -5 * 8 = -40
x = -5, y = -2, xy = -5 * -2 = 10
x = 7, y = 8, xy = 7 * 8 = 56
x = 7, y = -2, xy = 7 * -2 = -14
=> Possible values of xy are -40, -14, 10, 56
=> All options are possible
So, Answer will be A,B,D
Hope it helps!
Watch the following video to MASTER Absolute Values
