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If 12a + 3b = 1 and 7b – 2a = 9, what is the average (arithm
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10 Jan 2019, 06:40
10 Jan 2019, 06:40
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If 12a + 3b = 1 and 7b – 2a = 9, what is the average (arithmetic mean) of a and b ?
A) 0.1
B) 0.5
C) 1
D) 2.5
E) 5
A) 0.1
B) 0.5
C) 1
D) 2.5
E) 5
Re: If 12a + 3b = 1 and 7b – 2a = 9, what is the average (arithm
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10 Jan 2019, 09:20
10 Jan 2019, 09:20
Add 12a+3b= 1 and 7b-2a=9, then we will get 10a+10b=10 which results 10(a+b)=10. Thus a+b=1.
therefore, Arithmetic mean of a and b = a+b/2 =1/2 = 0.5
Therefore, the answer is B.
Please let me know if the answer is wrong.
Thank You.
therefore, Arithmetic mean of a and b = a+b/2 =1/2 = 0.5
Therefore, the answer is B.
Please let me know if the answer is wrong.
Thank You.
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Re: If 12a + 3b = 1 and 7b – 2a = 9, what is the average (arithm
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10 Jan 2019, 09:53
10 Jan 2019, 09:53
ARIJOSHI wrote:
Please let me know if the answer is wrong.
Thank You.
Thank You.
Perfect solution!
Cheers,
Brent
