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If 16x2 = 81 and x > 0, then what is the value of Indicate all such
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21 Feb 2022, 01:38
21 Feb 2022, 01:38
Expert Reply
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Question Stats:
47% (00:50) correct
52% (01:02) wrong based on 23 sessions
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If \(16x^2 = 81\) and x > 0, then what is the value of \(\sqrt{ x }\)?
Indicate all such values.
A. - 9/2
B. - 3/2
C. \(\sqrt{\frac{3}{2}}\)
D. 3/2
E. 9/4
Indicate all such values.
A. - 9/2
B. - 3/2
C. \(\sqrt{\frac{3}{2}}\)
D. 3/2
E. 9/4
Re: If 16x2 = 81 and x > 0, then what is the value of Indicate all such
[#permalink]
21 Feb 2022, 02:32
21 Feb 2022, 02:32
1
\(16x^2 = 81\) & \(x > 0\)
\(x^2 = \frac{81}{16}\)
\(x = \frac{9}{4}\)
In GRE, the square root is taken as a positive value.
\(\sqrt{ x }\) \(= \frac{3}{2}\)
Answer D
\(x^2 = \frac{81}{16}\)
\(x = \frac{9}{4}\)
In GRE, the square root is taken as a positive value.
\(\sqrt{ x }\) \(= \frac{3}{2}\)
Answer D
gmatclubot
Re: If 16x2 = 81 and x > 0, then what is the value of Indicate all such [#permalink]
21 Feb 2022, 02:32
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