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Re: If 2x + 3y = 5 and 3y + 6 = 0, then what is the value of x?
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13 Apr 2023, 16:55
Given the two equations:
2x + 3y = 5
3y + 6 = 0
We can solve for the value of x by substituting the value of y from equation 2 into equation 1.
From equation 2, we have:
3y + 6 = 0
Solving for y, we get:
3y = -6
y = -6/3
y = -2
Now, substituting y = -2 into equation 1:
2x + 3(-2) = 5
2x - 6 = 5
2x = 5 + 6
2x = 11
Dividing both sides by 2, we get:
x = 11/2
So, the value of x is 11/2, which is option (b).