GeminiHeat wrote:
If \(3x + 4y = -8\), and if \(x - 2y = \frac{1}{2}\), then \(x =\)
(A) -12
(B) \(-\frac{7}{5}\)
(C) \(\frac{1}{3}\)
(D) \(\frac{14}{5}\)
(E) 9
NOTE: For systems of equations questions, it is typically quicker to use the elimination method (over the substitution method)Given:
\(3x + 4y = -8\)
\(x - 2y = \frac{1}{2}\)
Take the bottom equation, and multiply both sides by \(2\), to get an equivalent equation:
\(3x + 4y = -8\)
\(2x - 4y = 1\)
Now, when we add the two equations, the y-terms cancel out to get: \(5x = -7\)
Divide both sides by \(5\) to get: \(x = \frac{-7}{5}\)
Answer: B
Cheers,
Brent