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If (4^1/3 ) n = 8, what is the value of n ?
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19 Aug 2021, 05:14
19 Aug 2021, 05:14
Expert Reply
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Question Stats:
90% (00:45) correct
9% (00:16) wrong based on 11 sessions
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If \((4^{\frac{1}{3}} )^n = 8\), what is the value of n ?
(A) 9/2
(B) 3√2
(C) 3
(D) 3/2
(E) 2
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
(A) 9/2
(B) 3√2
(C) 3
(D) 3/2
(E) 2
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
Re: If (4^1/3 ) n = 8, what is the value of n ?
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19 Aug 2021, 07:11
19 Aug 2021, 07:11
1
First we would make the base same. We will have 4=2^2 and 8=2^3.
Substituting the same in the given equation: (((2^2)^\(\frac{1}{3}\))^n) = 2^3
Now we can work with the powers as the base are now equal.
2*\(\frac{1}{3}\)*n = 3
2*n =3*3
n = \(\frac{9}{2} \)
Hence the answer is option A
Substituting the same in the given equation: (((2^2)^\(\frac{1}{3}\))^n) = 2^3
Now we can work with the powers as the base are now equal.
2*\(\frac{1}{3}\)*n = 3
2*n =3*3
n = \(\frac{9}{2} \)
Hence the answer is option A
gmatclubot
Re: If (4^1/3 ) n = 8, what is the value of n ? [#permalink]
19 Aug 2021, 07:11
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