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If 4 < a < 6 and 7 < b < 9, then 1/(b - a) is between
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02 Jan 2022, 06:45
02 Jan 2022, 06:45
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Question Stats:
70% (01:01) correct
30% (01:23) wrong based on 10 sessions
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If 4 < a < 6 and 7 < b < 9, then 1/(b - a) is between
(A) 1/3 and 1/5
(B) 1/2 and 1/5
(C) 1/5 and 1/3
(D) 1/2 and 1
(E) 1/5 and 1
(A) 1/3 and 1/5
(B) 1/2 and 1/5
(C) 1/5 and 1/3
(D) 1/2 and 1
(E) 1/5 and 1
Re: If 4 < a < 6 and 7 < b < 9, then 1/(b - a) is between
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02 Jan 2022, 19:54
02 Jan 2022, 19:54
1
\(4 < a < 6\) and \(7 < b < 9\)
We need the range of \(b - a\) so
The lowest value = Lowest value of \(b\) - highest value of \(a\) \(= 7 - 6 = 1\)
The highest value = Highest value of \(b\) - lowest value of \(a\) \(= 9 - 4 = 5\)
\(1 < b - a < 5\)
Inversing the inequality,
\(1 > \frac{1}{b-a} > \frac{1}{5}\)
\(\frac{1}{5} < \frac{1}{b-a} < 1\)
Answer E
We need the range of \(b - a\) so
The lowest value = Lowest value of \(b\) - highest value of \(a\) \(= 7 - 6 = 1\)
The highest value = Highest value of \(b\) - lowest value of \(a\) \(= 9 - 4 = 5\)
\(1 < b - a < 5\)
Inversing the inequality,
\(1 > \frac{1}{b-a} > \frac{1}{5}\)
\(\frac{1}{5} < \frac{1}{b-a} < 1\)
Answer E
gmatclubot
Re: If 4 < a < 6 and 7 < b < 9, then 1/(b - a) is between [#permalink]
02 Jan 2022, 19:54
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