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If 4 x^2 =8 2x , then which of the following could be the value of x?
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16 Jun 2021, 02:10
16 Jun 2021, 02:10
Expert Reply
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Question Stats:
65% (01:14) correct
34% (03:27) wrong based on 23 sessions
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If \(4^{x^2}=8^{2x}\), then which of the following could be the value of x?
Indicate all that apply.
–2
0
2
2.5
3
4
Indicate all that apply.
–2
0
2
2.5
3
4
Re: If 4 x^2 =8 2x , then which of the following could be the value of x?
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16 Jun 2021, 19:22
16 Jun 2021, 19:22
1
\(4x^2=8^{2x}\)
\(4x^2 = 4^{2x} * 2^{2x}\)
\(\frac{4x^2}{4^{2x}} = 2^{2x}\)
\(4^{x^2-2x} = 2^{2x}\)
\(2^{2x^2-4x} = 2^{2x}\)
\(2x^2-4x = 2x\)
\(2x^2-6x = 0\)
\(2x(x-3) = 0\)
\(x = 0\) OR \(3\)
You can also plug in the options.
Answer B E
\(4x^2 = 4^{2x} * 2^{2x}\)
\(\frac{4x^2}{4^{2x}} = 2^{2x}\)
\(4^{x^2-2x} = 2^{2x}\)
\(2^{2x^2-4x} = 2^{2x}\)
\(2x^2-4x = 2x\)
\(2x^2-6x = 0\)
\(2x(x-3) = 0\)
\(x = 0\) OR \(3\)
You can also plug in the options.
Answer B E
Re: If 4 x^2 =8 2x , then which of the following could be the value of x?
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17 Jun 2021, 00:58
17 Jun 2021, 00:58
Expert Reply
rx10 wrote:
\(4x^2=8^{2x}\)
\(4x^2 = 4^{2x} * 2^{2x}\)
\(\frac{4x^2}{4^{2x}} = 2^{2x}\)
\(4^{x^2-2x} = 2^{2x}\)
\(2^{2x^2-4x} = 2^{2x}\)
\(2x^2-4x = 2x\)
\(2x^2-6x = 0\)
\(2x(x-3) = 0\)
\(x = 0\) OR \(3\)
You can also plug in the options.
Answer B E
\(4x^2 = 4^{2x} * 2^{2x}\)
\(\frac{4x^2}{4^{2x}} = 2^{2x}\)
\(4^{x^2-2x} = 2^{2x}\)
\(2^{2x^2-4x} = 2^{2x}\)
\(2x^2-4x = 2x\)
\(2x^2-6x = 0\)
\(2x(x-3) = 0\)
\(x = 0\) OR \(3\)
You can also plug in the options.
Answer B E
Fixed a typo in the stem
