If 5x^2+ax+b/3x^2+7x+5
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24 Apr 2021, 08:11
\(\frac{5x^2+ax+b}{3x^2+7x+5}=x\) & \(3x^3+2x^2-b=0\)
\(b = 3x^3 + 2x^2\)
putting the value of \(b\) in the first equation
\(\frac{5x^2+ax+3x^3 + 2x^2}{3x^2+7x+5}\) = \(x\)
\(3x^3 + 7x^2 + ax\) = \(x(3x^2+7x+5)\) = \(3x^3 + 7x^2 + 5x\)
Comparing both the equation
\(a = 5\)