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If 5x^2+ax+b/3x^2+7x+5
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23 Apr 2021, 10:01
23 Apr 2021, 10:01
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92% (01:37) correct
7% (04:09) wrong based on 13 sessions
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If \(\frac{5x^2+ax+b}{3x^2+7x+5}=x\) and \(3x^3+2x^2-b=0\), where \(x \neq 0\), what is the value of a ?
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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5
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
If 5x^2+ax+b/3x^2+7x+5
[#permalink]
24 Apr 2021, 08:11
24 Apr 2021, 08:11
1
\(\frac{5x^2+ax+b}{3x^2+7x+5}=x\) & \(3x^3+2x^2-b=0\)
\(b = 3x^3 + 2x^2\)
putting the value of \(b\) in the first equation
\(\frac{5x^2+ax+3x^3 + 2x^2}{3x^2+7x+5}\) = \(x\)
\(3x^3 + 7x^2 + ax\) = \(x(3x^2+7x+5)\) = \(3x^3 + 7x^2 + 5x\)
Comparing both the equation
\(a = 5\)
\(b = 3x^3 + 2x^2\)
putting the value of \(b\) in the first equation
\(\frac{5x^2+ax+3x^3 + 2x^2}{3x^2+7x+5}\) = \(x\)
\(3x^3 + 7x^2 + ax\) = \(x(3x^2+7x+5)\) = \(3x^3 + 7x^2 + 5x\)
Comparing both the equation
\(a = 5\)
gmatclubot
If 5x^2+ax+b/3x^2+7x+5 [#permalink]
24 Apr 2021, 08:11
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